4y^2-9y-3=0

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Solution for 4y^2-9y-3=0 equation: 



4y^2-9y-3=0

a = 4; b = -9; c = -3;
Δ = b2-4ac
Δ = -92-4·4·(-3)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{129}}{2*4}=\frac{9-\sqrt{129}}{8}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{129}}{2*4}=\frac{9+\sqrt{129}}{8}
$

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